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Forums >> Revit Building >> Technical Support >> stair help with tread AND railing
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Joined: Wed, Aug 20, 2008
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So I have two pictures.
I have set the stair to go to the landing below. a simple straight run. 5'2" long, with 6 treads and 7 risers.
I set the stair rules. and I get a stair thats as short as possible. less than the 5'2 i need. I extend the line and it adds treads and risers instead of extending the threads to fill the run. then I moved the boundaries instead. got 7 rises but the railing is now horizontal. please help me...I just want a stair that I can set the rise and it will fill in the run with the desired number of treads...I cant do it!
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Stairs will behave differently depending on the version of REVIT and the method.
Not sure about the tread rised situation but the railing is not sloped becasue it does not fall within the width of the stair. The railing sketch can have an offset that will result in placing the outside the width of the stair but the actual sketch line must be within the stair width. Click the railing, edit the sketch and nudge it within the stair width and it will slope.
Also make sure the railing is 'hosted' (re-hosted) by the stair.
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Sorry - I don't understand what you are saying.
First, are you doing stair by sketch or component? What kind of stair is this?
Tread size is controlled by your stair properties. If doing stair by sketch, the number of treads is determined by how many risers you have. I doubt the dimension you show is between stair treads but tread to your landing.
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revit 2011 btw; The railing was over, nudging it worked like a charm.
@hub: the stair is made by sketching the run. setting the desired numbers of risers (to 7 in this case)...so the tread depth should be fluid. also its an existing stair and I just want to draw it properly like it is.
so this stair has max riser and min tread values set so that almost any stair will work, but it still has the tread depth locked in the properties (why?); AND it doesnt correspond with the actual actual tread depth shown by the dimension circled in red. also, the actual risers is 8! not 7....
ie. as the blue line gets bigger (to span the opening in the floor) the stair adds risers instead of making the treads longer to span the distance
Sorry this is all rambling.
What I need is a 5'2" long stair run that falls 4'-4.5" it has 6 treads and seven risers. t: 10-21/64" and r: 7-1/2"
I cant get revit to draw that
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The actual riser height is always going to be the difference between the top and bottom elevation of the stair / the # risers.
It also depands on if you set the 'begin with riser' and 'end with riser' of the stair type properties.
The tread depth should be what ever you sketch it at.
Edited on: Tue, Jul 2, 2013 at 4:13:18 PM
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g'day warchitect.
in your first diagram you have dimensioned in plan the going of the tread, not the actual tread (assuming there is an overhang or "toe" to the treads.) so the overhang value is the difference between actual and going value.
in oz, if we have a stair with 250mm going and a 25mm toe, our actual tread size is 275mm, etc
cheers
geoff
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Cool thanks for all the help. Was able to do everything. but I think I stumbles through it pretty badly. lol
still. measuring from one nosing of the stair to the other should get you the same as measuring the face if the rider to face of the riser.
but I guess my question really is this:
when you start a stair you set the begin and end levels. then you start drawing a run. but no matter what, the run always is some set number..why doesnt it let you draw the run line as long as you want, then divide the length by one less than the risers..(ie you have 20 long feet to fill, and you have to draw 5 risers at 6" say, so each tread should be streatched out 5 feet. 4 treads at 5' = 20')but the comp doesnt let you do that...is that not right?
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Don't use the Run method.
Draw the risers and boundary seperately. Then you can place things any where you want.
By using the Run method it follows the Tread and Riser rules of the Stair Type. (click the Edit Type button to access this information.
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