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Forums >> Revit Structure >> Technical Support >> Help with Geometry
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Joined: Wed, Mar 12, 2008
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I need a Geometry 101 lesson. I am trying to determine the lengths of three lines within a circle. I have all the information regarding the radius, the endpoing locations within the circle, and the angles of each line. What I don't have is a formula that links this information together and provides me with a line length. Can anyone help me with this? How can I find this length? See attached image. Thank you in advance!
Edited on: Sat, Dec 19, 2009 at 11:14:22 PM
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Your image doesn't highlight what information you know and what you want to find out...??
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Chris.
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Yes, I understand it doesn't match verbatim. I should clarify. Three of the five lines are unique. Two of them are at 90°, two of them are at 22.5°, and one of them is at 45°. Therefore, I have three unique line lengths I am looking for. What I know. The five lines are not radiating from the center of the circle. They are radiating from a point 45° from the center of the circle. Let us assume it is 4'-0" in each direction. The radius is 20'-0" The angles are as mentioned above. But, to be technical, they are located at 0°, 22.5°, 45°, 67.5°, and 90°. That is what I know. What I don't know, and what I want to find is: The length of each line (really, I only need to calculate the length of each unique line, thus 3) from the point they radiate to the point at which they terminate (at the 2-'-0" radius). Edited on: Sat, Dec 19, 2009 at 11:22:13 PM
Edited on: Sat, Dec 19, 2009 at 11:23:24 PM
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By the way. I am trying to build a complex nested family which I hope will be fully parametric. These line lengths are the missing link. Thanks, Matt
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You've probably already seen this, but it may help. http://mathforum.org/dr.math/faq/formulas/faq.circle.html And this which is more in line with what you are trying to achieve: http://www.gamedev.net/community/forums/topic.asp?topic_id=554266 And this one... Which does something very similar but more complex... http://www.physicsforums.com/showthread.php?t=185755&page=2 Edited on: Sun, Dec 20, 2009 at 1:00:54 AM
Edited on: Sun, Dec 20, 2009 at 1:23:54 AM
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Chris.
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The second link looks most helpful. Thank you very much sir.
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